Monochromatic light is incident on a plane interface AB between two media of refractive indices µ 1 and µ 2 (µ 2 > µ 1 ) at an angle θ as shown in figure. The angle θ is infinitesimally greater than the critical angle for two media so that total internal reflection takes place. Now, if a transparent slab DEFG of uniform thickness and having refractive index µ 3 is introduced on the interface as shown in the figure
If µ 3 < µ 1 , total internal reflection will take place at face GF
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(a, b)
sin C 1 = 
(interface AB)
sin C 2 = 
(interface GF)
Fig.
If µ 3 < µ 1 , 
< 
, hence, C 2 < C 1 and total internal reflection will take place at interface G.F.
If µ 3 > µ 1 , 
> 
, hence, C 2 > C 1
Therefore, C 2 > θ , hence, light ray will get refracted into the slab.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems